The number of calm road movie in Festival Lumière de Valmont equals 3 times the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Cinéma de Montreval equals the total number of movies in Festival Lumière de Valmont. The number of calm road movie in Cinéma de Montreval equals 4 plus the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 2.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define upbeat metropolis comedy in Festival Lumière de Valmont as r; so r = 2. Define calm road movie in Festival Lumière de Valmont as o; y = r = 2; so o = 3 * y = 3 * 2 = 6. Define total number of movies in Festival Lumière de Valmont as S; so S = r + o = 2 + 6 = 8. Define upbeat metropolis comedy in Cinéma de Montreval as X; so X = S = 8. Define calm road movie in Cinéma de Montreval as m; K = X = 8; so m = 4 + K = 4 + 8 = 12. Define total number of movies in Cinéma de Montreval as N; so N = X + m = 8 + 12 = 20. Answer: 20.


The number of public highschool in Evervale City equals the sum of the total number of schools in Hawkesbury, the number of elementary school in Hawkesbury, and the number of elementary school in Evervale City. The number of elementary school in Hawkesbury equals 3. The number of elementary school in Evervale City equals 3 plus the sum of the total number of schools in Hawkesbury and the number of elementary school in Hawkesbury.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Hawkesbury as T; so T = 3. Define total number of schools in Hawkesbury as W; so W = T = 3. Define elementary school in Evervale City as G; M = W + T = 3 + 3 = 6; so G = 3 + M = 3 + 6 = 9. Define public highschool in Evervale City as s; j = W + T = 3 + 3 = 6; so s = j + G = 6 + 9 = 15. Define total number of schools in Evervale City as v; so v = s + G = 15 + 9 = 24. Answer: 24.


The number of adult fox in Jefferson Circus equals 4. The number of adult wolf in Jefferson Circus equals 2 plus the number of adult fox in Jefferson Circus. The number of adult fox in Bundle Ranch equals 2 times the sum of the total number of adult animals in Jefferson Circus, the number of adult fox in Jefferson Circus, and the number of adult wolf in Jefferson Circus.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult fox in Jefferson Circus as l; so l = 4. Define adult wolf in Jefferson Circus as P; q = l = 4; so P = 2 + q = 2 + 4 = 6. Define total number of adult animals in Jefferson Circus as e; so e = l + P = 4 + 6 = 10. Define adult fox in Bundle Ranch as s; H = e + l = 10 + 4 = 14; R = H + P = 14 + 6 = 20; so s = 2 * R = 2 * 20 = 40. Define total number of adult animals in Bundle Ranch as y; so y = s = 40. Answer: 40.


The number of private middle school in Westhaven City equals 2 plus the difference between the number of regional medical school in Westhaven City and the number of private middle school in Evervale City. The number of regional medical school in Westhaven City equals 3 times the sum of the total number of schools in Evervale City and the number of private middle school in Evervale City. The number of private middle school in Evervale City equals 4.

Question: What is the total number of schools in Westhaven City?

Solution: Define private middle school in Evervale City as a; so a = 4. Define total number of schools in Evervale City as i; so i = a = 4. Define regional medical school in Westhaven City as V; m = i + a = 4 + 4 = 8; so V = 3 * m = 3 * 8 = 24. Define private middle school in Westhaven City as Q; n = V - a = 24 - 4 = 20; so Q = 2 + n = 2 + 20 = 22. Define total number of schools in Westhaven City as c; so c = V + Q = 24 + 22 = 46. Answer: 46.


The number of futuristic sci-fi movie in Cinéma de Montreval equals the total number of movies in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals 3. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the total number of movies in Festival de Clairmont. The number of calm road movie in Festival Lumière de Valmont equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Festival de Clairmont equals the number of intense detective thriller in Festival de Clairmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define intense detective thriller in Festival de Clairmont as b; so b = 3. Define calm road movie in Festival de Clairmont as C; so C = b = 3. Define total number of movies in Festival de Clairmont as g; so g = b + C = 3 + 3 = 6. Define upbeat metropolis comedy in Festival de Saint-Rivage as M; so M = g = 6. Define total number of movies in Festival de Saint-Rivage as P; so P = M = 6. Define futuristic sci-fi movie in Cinéma de Montreval as e; so e = P = 6. Define total number of movies in Cinéma de Montreval as z; so z = e = 6. Define calm road movie in Festival Lumière de Valmont as G; so G = z = 6. Define total number of movies in Festival Lumière de Valmont as o; so o = G = 6. Answer: 6.


The number of adult deer in Oakridge Riverside equals the total number of adult animals in Maple Creek. The number of adult deer in Maple Creek equals 1. The number of adult racoon in Maple Creek equals the number of adult deer in Maple Creek. The number of adult racoon in Oakridge Riverside equals the sum of the number of adult deer in Maple Creek, the total number of adult animals in Maple Creek, and the number of adult deer in Oakridge Riverside.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult deer in Maple Creek as M; so M = 1. Define adult racoon in Maple Creek as c; so c = M = 1. Define total number of adult animals in Maple Creek as l; so l = M + c = 1 + 1 = 2. Define adult deer in Oakridge Riverside as i; so i = l = 2. Define adult racoon in Oakridge Riverside as o; y = M + l = 1 + 2 = 3; so o = y + i = 3 + 2 = 5. Define total number of adult animals in Oakridge Riverside as D; so D = i + o = 2 + 5 = 7. Answer: 7.


The number of elementary school in Brightford equals 1. The number of regional medical school in Evervale City equals 2 times the total number of schools in Brightford. The number of elementary school in Evervale City equals 3. The number of regional medical school in Brightford equals 3 plus the number of elementary school in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Brightford as k; so k = 1. Define regional medical school in Brightford as P; f = k = 1; so P = 3 + f = 3 + 1 = 4. Define total number of schools in Brightford as g; so g = k + P = 1 + 4 = 5. Define regional medical school in Evervale City as j; u = g = 5; so j = 2 * u = 2 * 5 = 10. Define elementary school in Evervale City as C; so C = 3. Define total number of schools in Evervale City as J; so J = C + j = 3 + 10 = 13. Answer: 13.


The number of elementary school in Oakbridge City equals the number of private middle school in Oakbridge City. The number of elementary school in Riverton City equals 2 times the number of private middle school in Riverton City. The number of private middle school in Oakbridge City equals the sum of the total number of schools in Riverton City and the number of elementary school in Riverton City. The number of private middle school in Riverton City equals 4.

Question: What is the total number of schools in Oakbridge City?

Solution: Define private middle school in Riverton City as y; so y = 4. Define elementary school in Riverton City as b; N = y = 4; so b = 2 * N = 2 * 4 = 8. Define total number of schools in Riverton City as H; so H = y + b = 4 + 8 = 12. Define private middle school in Oakbridge City as B; so B = H + b = 12 + 8 = 20. Define elementary school in Oakbridge City as o; so o = B = 20. Define total number of schools in Oakbridge City as A; so A = B + o = 20 + 20 = 40. Answer: 40.


The number of culinarian school in Oakbridge City equals 4 plus the difference between the total number of schools in Shoreline City and the number of culinarian school in Shoreline City. The number of culinarian school in Shoreline City equals 2. The number of regional medical school in Oakbridge City equals 3 plus the sum of the total number of schools in Shoreline City and the number of culinarian school in Oakbridge City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Shoreline City as M; so M = 2. Define total number of schools in Shoreline City as i; so i = M = 2. Define culinarian school in Oakbridge City as r; a = i - M = 2 - 2 = 0; so r = 4 + a = 4 + 0 = 4. Define regional medical school in Oakbridge City as S; f = i + r = 2 + 4 = 6; so S = 3 + f = 3 + 6 = 9. Define total number of schools in Oakbridge City as V; so V = S + r = 9 + 4 = 13. Answer: 13.


The number of private middle school in Evervale City equals 3. The number of private middle school in Brightford equals 4 times the sum of the total number of schools in Westhaven City, the number of private middle school in Evervale City, and the total number of schools in Evervale City. The number of private middle school in Westhaven City equals 1 plus the total number of schools in Evervale City.

Question: What is the total number of schools in Brightford?

Solution: Define private middle school in Evervale City as O; so O = 3. Define total number of schools in Evervale City as k; so k = O = 3. Define private middle school in Westhaven City as t; b = k = 3; so t = 1 + b = 1 + 3 = 4. Define total number of schools in Westhaven City as n; so n = t = 4. Define private middle school in Brightford as i; u = n + O = 4 + 3 = 7; d = u + k = 7 + 3 = 10; so i = 4 * d = 4 * 10 = 40. Define total number of schools in Brightford as N; so N = i = 40. Answer: 40.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3 times the total number of movies in Golden Banana Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define upbeat metropolis comedy in Golden Banana Movie Festival as x; so x = 3. Define solemn period drama in Golden Banana Movie Festival as z; so z = x = 3. Define total number of movies in Golden Banana Movie Festival as q; so q = z + x = 3 + 3 = 6. Define solemn period drama in West Sahara Movie Festival as P; D = q = 6; so P = 3 * D = 3 * 6 = 18. Define upbeat metropolis comedy in West Sahara Movie Festival as Q; so Q = q + z = 6 + 3 = 9. Define total number of movies in West Sahara Movie Festival as e; so e = P + Q = 18 + 9 = 27. Answer: 27.


The number of adult crow in Maple Creek equals 2 plus the sum of the total number of adult animals in Beverly Forest, the number of adult eagle in Beverly Forest, and the number of adult parrot in Beverly Forest. The number of adult eagle in Beverly Forest equals 3. The number of adult parrot in Beverly Forest equals 4 plus the number of adult eagle in Beverly Forest.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult eagle in Beverly Forest as b; so b = 3. Define adult parrot in Beverly Forest as V; J = b = 3; so V = 4 + J = 4 + 3 = 7. Define total number of adult animals in Beverly Forest as M; so M = b + V = 3 + 7 = 10. Define adult crow in Maple Creek as U; H = M + b = 10 + 3 = 13; G = H + V = 13 + 7 = 20; so U = 2 + G = 2 + 20 = 22. Define total number of adult animals in Maple Creek as f; so f = U = 22. Answer: 22.


The number of intense detective thriller in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4 plus the sum of the total number of movies in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define intense detective thriller in Northwood Movie Festival as x; so x = 4. Define upbeat metropolis comedy in Northwood Movie Festival as V; k = x = 4; so V = 1 + k = 1 + 4 = 5. Define total number of movies in Northwood Movie Festival as i; so i = x + V = 4 + 5 = 9. Define intense detective thriller in Golden Banana Movie Festival as s; F = i + x = 9 + 4 = 13; h = F + V = 13 + 5 = 18; so s = 4 + h = 4 + 18 = 22. Define total number of movies in Golden Banana Movie Festival as j; so j = s = 22. Answer: 22.


The number of regional medical school in Glenfield City equals 3 plus the sum of the total number of schools in Brightford, the number of private middle school in Glenfield City, and the number of regional medical school in Brightford. The number of private middle school in Glenfield City equals 4. The number of regional medical school in Brightford equals 4 plus the number of private middle school in Glenfield City.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Glenfield City as N; so N = 4. Define regional medical school in Brightford as L; k = N = 4; so L = 4 + k = 4 + 4 = 8. Define total number of schools in Brightford as y; so y = L = 8. Define regional medical school in Glenfield City as M; m = y + N = 8 + 4 = 12; o = m + L = 12 + 8 = 20; so M = 3 + o = 3 + 20 = 23. Define total number of schools in Glenfield City as u; so u = N + M = 4 + 23 = 27. Answer: 27.


The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 1 plus the number of solemn period drama in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of futuristic sci-fi movie in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 plus the number of futuristic sci-fi movie in Northwood Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define futuristic sci-fi movie in Northwood Movie Festival as j; so j = 2. Define solemn period drama in Northwood Movie Festival as R; f = j = 2; so R = 4 + f = 4 + 2 = 6. Define upbeat metropolis comedy in Northwood Movie Festival as a; so a = j = 2. Define calm road movie in Northwood Movie Festival as v; J = R = 6; so v = 1 + J = 1 + 6 = 7. Define total number of movies in Northwood Movie Festival as m; P = j + a = 2 + 2 = 4; W = P + v = 4 + 7 = 11; so m = W + R = 11 + 6 = 17. Answer: 17.


The number of adult fox in South Zoo equals the difference between the total number of adult animals in Hamilton Farm and the number of adult bear in Hamilton Farm. The number of adult bear in South Zoo equals the number of adult fox in South Zoo. The number of adult fox in Hamilton Farm equals 3 times the number of adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals 1.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Hamilton Farm as W; so W = 1. Define adult fox in Hamilton Farm as y; F = W = 1; so y = 3 * F = 3 * 1 = 3. Define total number of adult animals in Hamilton Farm as x; so x = y + W = 3 + 1 = 4. Define adult fox in South Zoo as g; so g = x - W = 4 - 1 = 3. Define adult bear in South Zoo as Q; so Q = g = 3. Define total number of adult animals in South Zoo as z; so z = g + Q = 3 + 3 = 6. Answer: 6.


The number of calm road movie in Golden Banana Movie Festival equals 4. The number of solemn period drama in Golden Banana Movie Festival equals 2 times the number of calm road movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3 plus the sum of the total number of movies in Golden Banana Movie Festival, the number of calm road movie in Golden Banana Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define calm road movie in Golden Banana Movie Festival as E; so E = 4. Define solemn period drama in Golden Banana Movie Festival as B; N = E = 4; so B = 2 * N = 2 * 4 = 8. Define total number of movies in Golden Banana Movie Festival as k; so k = B + E = 8 + 4 = 12. Define upbeat metropolis comedy in Northwood Movie Festival as l; V = k + E = 12 + 4 = 16; Z = V + B = 16 + 8 = 24; so l = 3 + Z = 3 + 24 = 27. Define total number of movies in Northwood Movie Festival as m; so m = l = 27. Answer: 27.


The number of adult owl in Bundle Ranch equals 4. The number of adult parrot in Bundle Ranch equals 1 plus the number of adult owl in Bundle Ranch. The number of adult owl in Hamilton Farm equals the difference between the total number of adult animals in Bundle Ranch and the number of adult owl in Bundle Ranch. The number of adult parrot in Hamilton Farm equals the number of adult parrot in Bundle Ranch.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult owl in Bundle Ranch as w; so w = 4. Define adult parrot in Bundle Ranch as L; h = w = 4; so L = 1 + h = 1 + 4 = 5. Define total number of adult animals in Bundle Ranch as A; so A = w + L = 4 + 5 = 9. Define adult owl in Hamilton Farm as G; so G = A - w = 9 - 4 = 5. Define adult parrot in Hamilton Farm as I; so I = L = 5. Define total number of adult animals in Hamilton Farm as q; so q = G + I = 5 + 5 = 10. Answer: 10.


The number of adult fox in Maple Creek equals the sum of the number of adult racoon in Maple Creek, the number of adult fox in Beverly Forest, the total number of adult animals in Oakridge Riverside, and the number of adult fox in Cedar Valley. The number of adult fox in Pine Ridge equals 3. The number of adult fox in Oakridge Riverside equals 2. The number of adult racoon in Cedar Valley equals 2. The number of adult racoon in Beverly Forest equals the sum of the number of adult fox in Beverly Forest, the number of adult fox in Oakridge Riverside, and the total number of adult animals in Oakridge Riverside. The number of adult fox in Cedar Valley equals 2. The number of adult fox in Beverly Forest equals 1 plus the difference between the total number of adult animals in Oakridge Riverside and the number of adult fox in Oakridge Riverside. The number of adult racoon in Maple Creek equals 4.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult fox in Oakridge Riverside as P; so P = 2. Define total number of adult animals in Oakridge Riverside as i; so i = P = 2. Define adult fox in Beverly Forest as Z; C = i - P = 2 - 2 = 0; so Z = 1 + C = 1 + 0 = 1. Define adult racoon in Beverly Forest as S; w = Z + P = 1 + 2 = 3; so S = w + i = 3 + 2 = 5. Define total number of adult animals in Beverly Forest as l; so l = S + Z = 5 + 1 = 6. Answer: 6.


The number of adult racoon in Bundle Ranch equals 2. The number of adult wolf in South Zoo equals 3 plus the difference between the total number of adult animals in Bundle Ranch and the number of adult racoon in Bundle Ranch. The number of adult racoon in South Zoo equals 4 plus the difference between the number of adult racoon in Bundle Ranch and the total number of adult animals in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult racoon in Bundle Ranch as k; so k = 2. Define total number of adult animals in Bundle Ranch as M; so M = k = 2. Define adult wolf in South Zoo as H; v = M - k = 2 - 2 = 0; so H = 3 + v = 3 + 0 = 3. Define adult racoon in South Zoo as r; Q = k - M = 2 - 2 = 0; so r = 4 + Q = 4 + 0 = 4. Define total number of adult animals in South Zoo as E; so E = r + H = 4 + 3 = 7. Answer: 7.