The number of public highschool in Shoreline City equals the difference between the number of elementary school in Clearwater Bay and the number of elementary school in Ruby Bay. The number of elementary school in Riverton City equals 3. The number of elementary school in Clearwater Bay equals 2. The number of elementary school in Shoreline City equals 3. The number of elementary school in Ruby Bay equals 3. The number of private middle school in Clearwater Bay equals the number of elementary school in Clearwater Bay. The number of private middle school in Riverton City equals 4 times the number of elementary school in Riverton City. The number of regional medical school in Shoreline City equals 2 times the number of elementary school in Clearwater Bay. The number of private middle school in Shoreline City equals the number of elementary school in Ruby Bay. The number of regional medical school in Ruby Bay equals 1 plus the sum of the number of private middle school in Ruby Bay, the number of elementary school in Ruby Bay, and the number of public highschool in Riverton City. The number of public highschool in Clearwater Bay equals 3. The number of regional medical school in Riverton City equals 1 plus the sum of the total number of schools in Clearwater Bay, the number of elementary school in Clearwater Bay, and the number of public highschool in Clearwater Bay. The number of public highschool in Ruby Bay equals 4. The number of private middle school in Ruby Bay equals the number of public highschool in Riverton City. The number of public highschool in Riverton City equals 2 times the sum of the number of elementary school in Ruby Bay and the number of private middle school in Shoreline City.

Question: How many regional medical school does Riverton City have?

Solution: Define elementary school in Clearwater Bay as s; so s = 2. Define public highschool in Clearwater Bay as N; so N = 3. Define private middle school in Clearwater Bay as O; so O = s = 2. Define total number of schools in Clearwater Bay as X; k = s + N = 2 + 3 = 5; so X = k + O = 5 + 2 = 7. Define regional medical school in Riverton City as J; u = X + s = 7 + 2 = 9; h = u + N = 9 + 3 = 12; so J = 1 + h = 1 + 12 = 13. Answer: 13.


The number of upbeat metropolis comedy in Cinéma de Montreval equals 1 plus the sum of the total number of movies in Rêves de Belleville, the number of futuristic sci-fi movie in Rêves de Belleville, and the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 times the number of futuristic sci-fi movie in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 2.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define futuristic sci-fi movie in Rêves de Belleville as S; so S = 2. Define upbeat metropolis comedy in Rêves de Belleville as F; a = S = 2; so F = 2 * a = 2 * 2 = 4. Define total number of movies in Rêves de Belleville as O; so O = S + F = 2 + 4 = 6. Define upbeat metropolis comedy in Cinéma de Montreval as A; j = O + S = 6 + 2 = 8; z = j + F = 8 + 4 = 12; so A = 1 + z = 1 + 12 = 13. Define total number of movies in Cinéma de Montreval as c; so c = A = 13. Answer: 13.


The number of culinarian school in Glenfield City equals 4. The number of public highschool in Glenfield City equals the sum of the total number of schools in Evervale City, the number of public highschool in Evervale City, and the number of culinarian school in Evervale City. The number of culinarian school in Evervale City equals 4. The number of public highschool in Evervale City equals 2.

Question: What is the total number of schools in Glenfield City?

Solution: Define culinarian school in Evervale City as C; so C = 4. Define public highschool in Evervale City as M; so M = 2. Define total number of schools in Evervale City as n; so n = C + M = 4 + 2 = 6. Define public highschool in Glenfield City as Y; T = n + M = 6 + 2 = 8; so Y = T + C = 8 + 4 = 12. Define culinarian school in Glenfield City as q; so q = 4. Define total number of schools in Glenfield City as N; so N = q + Y = 4 + 12 = 16. Answer: 16.


The number of public highschool in Evervale City equals 2. The number of public highschool in Brightford equals 1 plus the total number of schools in Evervale City. The number of regional medical school in Evervale City equals the number of public highschool in Evervale City. The number of regional medical school in Brightford equals 3 times the total number of schools in Evervale City.

Question: What is the total number of schools in Brightford?

Solution: Define public highschool in Evervale City as D; so D = 2. Define regional medical school in Evervale City as m; so m = D = 2. Define total number of schools in Evervale City as U; so U = D + m = 2 + 2 = 4. Define public highschool in Brightford as B; v = U = 4; so B = 1 + v = 1 + 4 = 5. Define regional medical school in Brightford as z; l = U = 4; so z = 3 * l = 3 * 4 = 12. Define total number of schools in Brightford as q; so q = B + z = 5 + 12 = 17. Answer: 17.


The number of solemn period drama in Verdi Movie Festival equals 2 times the number of intense detective thriller in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2 plus the total number of movies in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2. The number of intense detective thriller in Verdi Movie Festival equals 4.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define intense detective thriller in Verdi Movie Festival as a; so a = 4. Define solemn period drama in Verdi Movie Festival as q; L = a = 4; so q = 2 * L = 2 * 4 = 8. Define total number of movies in Verdi Movie Festival as N; so N = q + a = 8 + 4 = 12. Define solemn period drama in West Sahara Movie Festival as P; G = N = 12; so P = 2 + G = 2 + 12 = 14. Define intense detective thriller in West Sahara Movie Festival as k; so k = 2. Define total number of movies in West Sahara Movie Festival as y; so y = P + k = 14 + 2 = 16. Answer: 16.


The number of adult racoon in South Zoo equals 3 times the number of adult fox in South Zoo. The number of adult fox in South Zoo equals 2. The number of adult fox in Hamilton Farm equals 4 times the sum of the total number of adult animals in South Zoo, the number of adult fox in South Zoo, and the number of adult racoon in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult fox in South Zoo as Y; so Y = 2. Define adult racoon in South Zoo as m; f = Y = 2; so m = 3 * f = 3 * 2 = 6. Define total number of adult animals in South Zoo as d; so d = Y + m = 2 + 6 = 8. Define adult fox in Hamilton Farm as e; G = d + Y = 8 + 2 = 10; A = G + m = 10 + 6 = 16; so e = 4 * A = 4 * 16 = 64. Define total number of adult animals in Hamilton Farm as w; so w = e = 64. Answer: 64.


The number of public highschool in Brightford equals the sum of the number of regional medical school in Brightford, the number of culinarian school in Evervale City, and the total number of schools in Evervale City. The number of regional medical school in Brightford equals 3 plus the difference between the total number of schools in Evervale City and the number of culinarian school in Evervale City. The number of culinarian school in Evervale City equals 4.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Evervale City as p; so p = 4. Define total number of schools in Evervale City as U; so U = p = 4. Define regional medical school in Brightford as O; c = U - p = 4 - 4 = 0; so O = 3 + c = 3 + 0 = 3. Define public highschool in Brightford as J; u = O + p = 3 + 4 = 7; so J = u + U = 7 + 4 = 11. Define total number of schools in Brightford as w; so w = O + J = 3 + 11 = 14. Answer: 14.


The number of culinarian school in Evervale City equals 3 times the sum of the total number of schools in Glenfield City and the number of public highschool in Evervale City. The number of culinarian school in Glenfield City equals 4. The number of public highschool in Evervale City equals 4 plus the difference between the total number of schools in Glenfield City and the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Glenfield City as C; so C = 4. Define total number of schools in Glenfield City as t; so t = C = 4. Define public highschool in Evervale City as q; r = t - C = 4 - 4 = 0; so q = 4 + r = 4 + 0 = 4. Define culinarian school in Evervale City as f; Q = t + q = 4 + 4 = 8; so f = 3 * Q = 3 * 8 = 24. Define total number of schools in Evervale City as c; so c = f + q = 24 + 4 = 28. Answer: 28.


The number of regional medical school in Evervale City equals the number of culinarian school in Evervale City. The number of regional medical school in Hawkesbury equals 1 plus the number of culinarian school in Hawkesbury. The number of culinarian school in Evervale City equals 2. The number of culinarian school in Hawkesbury equals 3 times the total number of schools in Evervale City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Evervale City as e; so e = 2. Define regional medical school in Evervale City as z; so z = e = 2. Define total number of schools in Evervale City as l; so l = z + e = 2 + 2 = 4. Define culinarian school in Hawkesbury as A; s = l = 4; so A = 3 * s = 3 * 4 = 12. Define regional medical school in Hawkesbury as W; i = A = 12; so W = 1 + i = 1 + 12 = 13. Define total number of schools in Hawkesbury as B; so B = A + W = 12 + 13 = 25. Answer: 25.


The number of elementary school in Glenfield City equals 2. The number of culinarian school in Glenfield City equals the sum of the number of elementary school in Hawkesbury, the total number of schools in Hawkesbury, the number of culinarian school in Hawkesbury, and the number of private middle school in Glenfield City. The number of culinarian school in Evervale City equals 4 plus the difference between the total number of schools in Hawkesbury and the number of elementary school in Hawkesbury. The number of private middle school in Evervale City equals 2. The number of culinarian school in Hawkesbury equals the number of private middle school in Glenfield City. The number of elementary school in Hawkesbury equals 2 plus the sum of the number of private middle school in Glenfield City and the number of culinarian school in Hawkesbury. The number of private middle school in Glenfield City equals 4. The number of public highschool in Evervale City equals 4 plus the difference between the number of elementary school in Glenfield City and the number of culinarian school in Hawkesbury.

Question: How many culinarian school does Evervale City have?

Solution: Define private middle school in Glenfield City as Z; so Z = 4. Define culinarian school in Hawkesbury as n; so n = Z = 4. Define elementary school in Hawkesbury as j; p = Z + n = 4 + 4 = 8; so j = 2 + p = 2 + 8 = 10. Define total number of schools in Hawkesbury as s; so s = j + n = 10 + 4 = 14. Define culinarian school in Evervale City as C; G = s - j = 14 - 10 = 4; so C = 4 + G = 4 + 4 = 8. Answer: 8.


The number of regional medical school in Riverton City equals 3. The number of regional medical school in Ruby Bay equals the sum of the total number of schools in Riverton City, the number of regional medical school in Riverton City, and the number of culinarian school in Riverton City. The number of culinarian school in Ruby Bay equals 4. The number of culinarian school in Riverton City equals the number of regional medical school in Riverton City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define regional medical school in Riverton City as K; so K = 3. Define culinarian school in Riverton City as S; so S = K = 3. Define total number of schools in Riverton City as u; so u = K + S = 3 + 3 = 6. Define regional medical school in Ruby Bay as o; L = u + K = 6 + 3 = 9; so o = L + S = 9 + 3 = 12. Define culinarian school in Ruby Bay as l; so l = 4. Define total number of schools in Ruby Bay as y; so y = o + l = 12 + 4 = 16. Answer: 16.


The number of upbeat metropolis comedy in Rêves de Belleville equals 2. The number of futuristic sci-fi movie in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Cinéma de Montreval equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 times the total number of movies in Festival de Clairmont. The number of calm road movie in Cinéma de Montreval equals 2 times the total number of movies in Rêves de Belleville. The number of calm road movie in Festival Lumière de Valmont equals the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals 2 plus the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Festival de Clairmont equals 4 plus the number of upbeat metropolis comedy in Festival de Clairmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as V; so V = 3. Define futuristic sci-fi movie in Festival de Clairmont as e; F = V = 3; so e = 4 + F = 4 + 3 = 7. Define total number of movies in Festival de Clairmont as p; so p = V + e = 3 + 7 = 10. Define calm road movie in Festival Lumière de Valmont as M; so M = p = 10. Define upbeat metropolis comedy in Festival Lumière de Valmont as D; O = p = 10; so D = 3 * O = 3 * 10 = 30. Define total number of movies in Festival Lumière de Valmont as a; so a = M + D = 10 + 30 = 40. Answer: 40.


The number of adult fox in Cedar Valley equals 3. The number of adult wolf in Maple Creek equals 4 times the sum of the total number of adult animals in Cedar Valley, the number of adult fox in Cedar Valley, and the number of adult wolf in Cedar Valley. The number of adult wolf in Cedar Valley equals 3 times the number of adult fox in Cedar Valley.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult fox in Cedar Valley as x; so x = 3. Define adult wolf in Cedar Valley as c; M = x = 3; so c = 3 * M = 3 * 3 = 9. Define total number of adult animals in Cedar Valley as R; so R = x + c = 3 + 9 = 12. Define adult wolf in Maple Creek as u; l = R + x = 12 + 3 = 15; p = l + c = 15 + 9 = 24; so u = 4 * p = 4 * 24 = 96. Define total number of adult animals in Maple Creek as G; so G = u = 96. Answer: 96.


The number of elementary school in Oakbridge City equals the number of regional medical school in Oakbridge City. The number of public highschool in Riverton City equals the sum of the number of elementary school in Riverton City, the number of elementary school in Oakbridge City, and the total number of schools in Oakbridge City. The number of culinarian school in Oakbridge City equals the sum of the number of regional medical school in Oakbridge City and the number of public highschool in Oakbridge City. The number of regional medical school in Oakbridge City equals the number of public highschool in Oakbridge City. The number of public highschool in Oakbridge City equals the number of elementary school in Riverton City. The number of elementary school in Riverton City equals 1. The number of culinarian school in Riverton City equals 1. The number of regional medical school in Riverton City equals 3 times the number of culinarian school in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define elementary school in Riverton City as J; so J = 1. Define public highschool in Oakbridge City as z; so z = J = 1. Define regional medical school in Oakbridge City as f; so f = z = 1. Define culinarian school in Oakbridge City as o; so o = f + z = 1 + 1 = 2. Define elementary school in Oakbridge City as h; so h = f = 1. Define total number of schools in Oakbridge City as u; H = o + f = 2 + 1 = 3; V = H + z = 3 + 1 = 4; so u = V + h = 4 + 1 = 5. Answer: 5.


The number of adult wolf in Cedar Valley equals the number of adult wolf in Maple Creek. The number of adult wolf in Maple Creek equals 2. The number of adult fox in Maple Creek equals 2 times the number of adult wolf in Maple Creek. The number of adult fox in Cedar Valley equals the difference between the total number of adult animals in Maple Creek and the number of adult wolf in Maple Creek.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Maple Creek as q; so q = 2. Define adult fox in Maple Creek as n; s = q = 2; so n = 2 * s = 2 * 2 = 4. Define total number of adult animals in Maple Creek as R; so R = n + q = 4 + 2 = 6. Define adult wolf in Cedar Valley as b; so b = q = 2. Define adult fox in Cedar Valley as N; so N = R - q = 6 - 2 = 4. Define total number of adult animals in Cedar Valley as U; so U = N + b = 4 + 2 = 6. Answer: 6.


The number of adult parrot in Oakridge Riverside equals 2 times the sum of the total number of adult animals in Beverly Forest and the number of adult eagle in Beverly Forest. The number of adult parrot in Cedar Valley equals 3. The number of adult eagle in Beverly Forest equals 3. The number of adult blue jay in Beverly Forest equals the total number of adult animals in Cedar Valley.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult parrot in Cedar Valley as E; so E = 3. Define total number of adult animals in Cedar Valley as d; so d = E = 3. Define adult blue jay in Beverly Forest as W; so W = d = 3. Define adult eagle in Beverly Forest as Y; so Y = 3. Define total number of adult animals in Beverly Forest as V; so V = W + Y = 3 + 3 = 6. Define adult parrot in Oakridge Riverside as K; z = V + Y = 6 + 3 = 9; so K = 2 * z = 2 * 9 = 18. Define total number of adult animals in Oakridge Riverside as R; so R = K = 18. Answer: 18.